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In an acute triangle A B C if sides a , ...

In an acute triangle `A B C` if sides `a , b` are constants and the base angles `Aa n dB` vary, then show that `(d A)/(sqrt(a^2-b^2sin^2A))=(d B)/(sqrt(b^2-a^2sin^2B))`

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The correct Answer is:
`(dB)/(sqrt(b^(2)-a^(2)sin^(2)B))`
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