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If ax^(2)+by^(2)=1 cut a'x^(2)+b'y^(2)=1...

If `ax^(2)+by^(2)=1` cut `a'x^(2)+b'y^(2)=1` orthogonally, then

A

`(1)/(a)-(1)/(a')=(1)/(b)-(1)/(b')`

B

`(1)/(a)+(1)/(a')=(1)/(b)+(1)/(b')`

C

`(1)/(a)+(1)/(b)=(1)/(a')+(1)/(b')`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
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