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In triangle ABC let tanA=1, tanB= 2, tan...

In triangle ABC let tanA=1, tanB= 2, tanC=3 and c= 3, The radius of the circle circumscribing the triangle ABC, is equal to

A. ` (sqrt10)/(2)`
B. `sqrt5`
C. `sqrt10`
D. `(sqrt5)/(2)`

A

` (sqrt10)/(2)`

B

`sqrt5`

C

`sqrt10`

D

`(sqrt5)/(2)`

Text Solution

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A, B, C, D
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ARIHANT MATHS-PROPERTIES AND SOLUTION OF TRIANGLES -Exercise (Questions Asked In Previous 13 Years Exam)
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