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perpendiculars are drawn from the angles...

perpendiculars are drawn from the angles `A , Ba n dC` of an acute-angled triangle on the opposite sides, and produced to meet the circumscribing circle. If these produced parts are `alpha,beta,gamma` , respectively, then show that `a/alpha+b/beta+c/gamma=2(tanA+tanB+t a nC)dot`

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The correct Answer is:
`(a)/(alpha) +(b)/(beta)+ (c)/(gamma) =2 (tan A+ tan B+ tan C)`
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ARIHANT MATHS-PROPERTIES AND SOLUTION OF TRIANGLES -Exercise (Questions Asked In Previous 13 Years Exam)
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