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ABCD is a trapezium such that A B||C Da ...

ABCD is a trapezium such that `A B||C Da n dC B` is perpendicular to them. If `/_A D B=theta,B C=p ,a n dC D=q` , show that `A B=((p^2+q^2)sintheta)/(pcostheta+qsintheta)`

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The correct Answer is:
`AB=((p^(2)+q^(2))sin theta)/(q sin theta+p cos theta)`
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