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If the sides of a triangle are in A.P., and its greatest angle exceeds the least angle by `alpha`, show that the sides are in the ratio `1+x :1:1-x`, , where `x = sqrt((1- cos alpha)/(7 - cos alpha))`

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Thus, the sides are in the ratio `1+x :1:1:1-x.`
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ARIHANT MATHS-PROPERTIES AND SOLUTION OF TRIANGLES -Exercise (Questions Asked In Previous 13 Years Exam)
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