In a `Delta ABC, if a =3, b=4, c=5,` then find the distance between its incentre and circumcentre.

Find the distance between the circumcentre and the incentre of the DeltaABC.

The vertices of a triangle are (6, 0), (0, 6) and (6, 6). The distance between its circumcentre and centroid is :

In Delta ABC it is given distance between the circumcentre (O) and orthocentre (H) is R sqrt(1-8 cos A cos B cos C) . If Q is the midopoint of OH, then AQ is

In Delta ABC , If a =4 , b=3 and COS(A-B) =3/4, then

Find the distance between points : A(2,3,5) and B (4, 3, 1).

The vertices of a triangle are A(0, 0), B(0, 2) and C(2, 0). The distance between circumcentre and orthocentre is

In a Delta ABC the equation of the side BC is 2x-y =3 and its circumcentre and orthocentre are (2,4) and (1,2) respectively . Circumradius of Delta ABC is

In a Delta ABC the equation of the side BC is 2x-y =3 and its circumcentre and orthocentre are (2,4) and (1,2) respetively . sin B.sin C=

In a Delta ABC the equation of the side BC is 2x-y =3 and its circumcentre and orthocentre are (2,4) and (1,2) respetively . The distance of orthocentre from vertex A is

In a triangle ABC, if a = 18, b = 24 and c = 30, find sin A, sin B and sin C.