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In the given figure, AB is the diameter ...

In the given figure, AB is the diameter of the circle, centered at O. If `angle COA =60^(@), AB=2r, Ac=d and CD=l,` then l is equal to

A

`dsqrt3`

B

`(d)/(sqrt3)`

C

`3d`

D

`(sqrt3d)/(2)`

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