Home
Class 12
MATHS
Find dy/dx , if x = cos(theta) and y = s...

Find `dy/dx , if x = cos(theta) and y = sin(2theta)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • PROPERTIES AND SOLUTION OF TRIANGLES

    ARIHANT MATHS|Exercise PROPERTIES AND SOLUTIONS OF TRIANGLES EXERCISE 5: MATCHING TYPE QUESTIONS|4 Videos
  • PROPERTIES AND SOLUTION OF TRIANGLES

    ARIHANT MATHS|Exercise Exercise (Single Integer Answer Type Questions)|16 Videos
  • PROPERTIES AND SOLUTION OF TRIANGLES

    ARIHANT MATHS|Exercise Exercise (Statement I And Ii Type Questions)|15 Videos
  • PRODUCT OF VECTORS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|52 Videos
  • SEQUENCES AND SERIES

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|38 Videos

Similar Questions

Explore conceptually related problems

If x and y are connected parameterically by the equation , without eliminating the parameter , find dy/dx x = a cos(theta) , y = b sin(theta)

Find (d^2y)/(dx^2) if x= cos theta, y = a sin theta)

Find (d^2y)/dx^2 , if x = a (theta - sin theta), y = a(1+cos theta)

Find dy/dx when x = a (cos theta + theta sin theta) , y = a (sin theta - theta cos theta).

If x and y are connected parametrically by the equations given in Exercises 1 to 10, without eliminating the parameter, Find dy/dx : x = a(cos theta + theta sin theta), y = a(sin theta - theta cos theta)

If x and y are connected parametrically by the equations given in Exercises 1 to 10, without eliminating the parameter, Find dy/dx : : x = a cos theta, y = b cos theta

Find (dy)/(dx) if x = sin t and y = cos 2t .

If x and y are connected parametrically by the equations given in Exercises 1 to 10, without eliminating the parameter, Find dy/dx : x = cos theta - cos 2theta, y = sin theta - sin 2theta

Find (d^2)/(dx^2) in the following : If x = a cos^3 theta and y = a sin^3 theta , then find the value of d^2y/dx^2) at theta = pi/6

ARIHANT MATHS-PROPERTIES AND SOLUTION OF TRIANGLES -Exercise (Passage Based Questions)
  1. Let ABC to be an acute triangle with BC=a,CA =b and AB=c, where a ne ...

    Text Solution

    |

  2. In an acute angled triangle ABC, let AD, BE and CF be the perpendicula...

    Text Solution

    |

  3. In an acute angle Delta ABC, let AD, BE and CF be the perpendicular fr...

    Text Solution

    |

  4. In an acute angle Delta ABC, let AD, BE and CF be the perpendicular fr...

    Text Solution

    |

  5. Let a,b, c are the sides opposite to angles A, B , C respectively in a...

    Text Solution

    |

  6. Let a,b, c are the sides opposite to angles A, B , C respectively in a...

    Text Solution

    |

  7. Let a,b, c are the sides opposite to angles A, B , C respectively in a...

    Text Solution

    |

  8. Find dy/dx , if x = 4/t and y = 4t

    Text Solution

    |

  9. If x and y are connected parametrically by the equation , without elim...

    Text Solution

    |

  10. Find dy/dx , if x = a sint , y = a(cost + log (tan (t/2))

    Text Solution

    |

  11. Find dy/dx , if x = cos(theta) and y = sin(2theta)

    Text Solution

    |

  12. Differentiate the following function w.r.t x cos^(-1)x/(2x+7)^(1...

    Text Solution

    |

  13. Consider a triangle ABC, where x,y,z are the length of perpendicular d...

    Text Solution

    |

  14. Consider a triangle ABC, where x,y,z are the length of perpendicular d...

    Text Solution

    |

  15. Consider a triangle ABC, where x,y,z are the length of perpendicular d...

    Text Solution

    |

  16. AL, BM and CN are perpendicular from angular points of a triangle ABC ...

    Text Solution

    |

  17. The angle of triangle A, B, C are in AP and C=3A . Find angle B

    Text Solution

    |

  18. AL, BM and CN are perpendicular from angular points of a triangle ABC ...

    Text Solution

    |

  19. AL, BM and CN are perpendicular from angular points of a triangle ABC ...

    Text Solution

    |

  20. Differentiate the following w.r.t x (2x^2-6x+4)^3

    Text Solution

    |