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Internal bisector of /A of triangle ABC ...

Internal bisector of `/_A` of triangle ABC meets side BC at D. A line drawn through D perpendicular to AD intersects the side AC at E and the side AB at F. If a, b, c represent sides of `DeltaABC`, then

A

AE is HM of b and a

B

`AD=(2bc)/(b+c)cos ""A/2`

C

`EF=(4bc)/(b+c) sin ""A/2`

D

`Delta AEF` is isosceles

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The correct Answer is:
A, B, C, D
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