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The last two digits of the number 19^(9...

The last two digits of the number ` 19^(9^(4))`is

A

19

B

29

C

39

D

81

Text Solution

Verified by Experts

The correct Answer is:
a
`because 19^(9^(4)) = (20 -1)^(9^(4)) = (20-1)^(6521) = - 1 + (6521)xx20 + ` multiple of 100
`= - 1 + 20 + ` multiple of 100
= 19 multiple of 100
` thereofre ` Last two digits of the number ` 19^(9^(4)) is 19` .
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ARIHANT MATHS-BIONOMIAL THEOREM-Exercise (Single Option Correct Type Questions)
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  11. Sum of last three digits of the number N=7^(100)-3^(100) is.

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  12. If 5^(99) is divided by 13, the remainder is

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  13. Find the value of {3^(2003)//28}, w h e r e{dot} denotes the fractiona...

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  14. The value of sum(r=0)^(20)r(20-r)(^(20)Cr)^2 is equal to 400^(39)C(20)...

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