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Find the equation of the circle having t...

Find the equation of the circle having the lines `x^2+2xy+3x+6y=0` as its normal and having size just sufficient to contain the circle `x(x-4)+y(y-3)=0`

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The correct Answer is:
or `x^(2)+y^(2)+6x-3y-54=0`
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Knowledge Check

  • The radius of the circle having the lines 3x - 4y + 4 = 0 and 6x - 8y - 7 = 0 as tangents is :

    A
    1
    B
    `1/2`
    C
    `2/3`
    D
    `3/4`

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