A circle of constant radius `a` passes through the origin `O` and cuts the axes of coordinates at points `P` and `Q` . Then the equation of the locus of the foot of perpendicular from `O` to `P Q` is

Options

A. `(A) (x^2+y^2)(1/(x^2)+1/(y^2))=4a^2`
B. `(B) (x^2+y^2)^2(1/(x^2)+1/(y^2))=a^2`
C. `(C) (x^2+y^2)^2(1/(x^2)+1/(y^2))=4a^2`
D. `(D) (x^2+y^2)(1/(x^2)+1/(y^2))=a^2`

Answer

which is the required locus.