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If one end of a diameter of the circle 2...

If one end of a diameter of the circle `2x^(2)+2y^(2)-4x-8y+2=0` is (-1,2), then the other end of the diameter is

A

(2,1)

B

(3,2)

C

(4,3)

D

(5,4)

Text Solution

Verified by Experts

The correct Answer is:
B
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