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The circle x^2+y^2=4 cuts the line joini...

The circle `x^2+y^2=4 `cuts the line joining the points `A(1, 0)` and `B(3, 4)` in two points `P` and `Q`. Let `(BP)/(PA)=alpha` and `(BQ)/(QA)=beta`. Then `alpha` and `beta` are roots of the quadratic equation

A

`x^(2)+2x+7=0`

B

`3x^(2)+2x-21=0`

C

`2x^(2)+3x-27=0`

D

None of these

Text Solution

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The correct Answer is:
B
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