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The locus of the mid points of the chord...

The locus of the mid points of the chords of the circle `x^2+y^2+4x-6y-12=0` which subtend an angle of `pi/3`radians at its circumference is:

A

`(x+2)^(2)+(y-3)^(2)=6.25`

B

`(x-2)^(2)+(y+3)^(2)=6.25`

C

`(x+2)^(2)+(y-3)^(2)=18.75`

D

`(x+2)^(2)+(y+3)^(2)=18.75`

Text Solution

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The correct Answer is:
A
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