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If the tangent to the ellipse x^2 +4y^2=...

If the tangent to the ellipse `x^2 +4y^2=16` at the point `theta` normal to the circle `x^2 +y^2-8x-4y=0` then `theta` is equal to

A

`pi/2`

B

`pi/4`

C

0

D

`-pi/4`

Text Solution

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The correct Answer is:
A, C
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