Home
Class 12
MATHS
The number of points on the ellipse (x^2...

The number of points on the ellipse `(x^2)/(50)+(y^2)/(20)=1` from which a pair of perpendicular tangents is drawn to the ellipse `(x^2)/(16)+(y^2)/9=1` is 0 (b) 2 (c) 1 (d) 4

Text Solution

Verified by Experts

The correct Answer is:
4
Promotional Banner

Topper's Solved these Questions

  • ELLIPSE

    ARIHANT MATHS|Exercise Ellipse Exercise 5: Matching Type Questions|3 Videos

  • ELLIPSE

    ARIHANT MATHS|Exercise Exercise (Statement I And Ii Type Questions)|8 Videos

  • ELLIPSE

    ARIHANT MATHS|Exercise Exercise (Passage Based Questions)|15 Videos

  • DY / DX AS A RATE MEASURER AND TANGENTS, NORMALS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|7 Videos

  • ESSENTIAL MATHEMATICAL TOOLS

    ARIHANT MATHS|Exercise Exercise (Single Integer Answer Type Questions)|3 Videos

Similar Questions

Explore conceptually related problems

The number of points on the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=3 from which mutually perpendicular tangents can be drawn to the circle x^2+y^2=a^2 is/are (a)0 (b) 2 (c) 3 (d) 4

The number of points outside the hyperbola x^2/9-y^2/16=1 from where two perpendicular tangents can be drawn to the hyperbola are:

Find the area bounded by the ellipse x^(2)/16+y^(2)/9=1

The maximum distance of the centre of the ellipse (x^(2))/(16) +(y^(2))/(9) =1 from the chord of contact of mutually perpendicular tangents of the ellipse is

Area bounded by the ellipse : x^2/16 + y^2/9 = 1 is :

The distance of a point on the ellipse (x^2)/6+(y^2)/2=1 from the center is 2. Then the eccentric angle of the point is

Find the length of latus rectum of the ellipse. x^2/16+y^2/9=1 .

The locus of the point of intersection of two prependicular tangents of the ellipse x^(2)/9+y^(2)/4=1 is

the centre of the ellipse ((x+y-2)^(2))/(9)+((x-y)^(2))/(16)=1 , is