Home
Class 12
MATHS
The locus of the foot of prependicular d...

The locus of the foot of prependicular drawn from the center of the ellipse `x^(2)+3y^(2)=6` on any tangent to it is

A

`(x^(2)+y^(2))^(2)=6x^(2)+2y^(2)`

B

`(x^(2)+y^(2))^(2)=6x^(2)-2y^(2)`

C

`(x^(2)-y^(2))^(2)=6x^(2)+2y^(2)`

D

`(x^(2)-y^(2))^(2)=6x^(2)-2y^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • ELLIPSE

    ARIHANT MATHS|Exercise Exercise (Subjective Type Questions)|3 Videos

  • DY / DX AS A RATE MEASURER AND TANGENTS, NORMALS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|7 Videos

  • ESSENTIAL MATHEMATICAL TOOLS

    ARIHANT MATHS|Exercise Exercise (Single Integer Answer Type Questions)|3 Videos

Similar Questions

Explore conceptually related problems

The locus of the foot of the perpendicular from the centre of the ellipse x^2/a^2+y^2/b^2=1 on any tangent is given by (x^2 + y^2)^2 = lx^2+my^2 , where:

Find the locus of the foot of the perpendicular drawn from the center upon any tangent to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1.

The locus of the point of intersection of two prependicular tangents of the ellipse x^(2)/9+y^(2)/4=1 is

Find the foot of perpendicular drawn from origin to the plane 2x+3y+4z-12=0

find the foot of perpendicular drawn from the point (2,-3,5) on the plane 3x+4y-2z=20

Let d be the perpendicular distance from the centre of the ellipse x^2/a^2+y^2/b^2=1 to the tangent drawn at a point P on the ellipse. If F_1 & F_2 are the two foci of the ellipse, then show the (PF_1-PF_2)^2=4a^2(1-b^2/d^2) .

Find the coordinates of the foot of the perpendicular drawn from the point (2,3) to the line y=3x+4

If P is the length of perpendicluar drawn from the origin to any normal to the ellipse x^(2)/25+y^(2)/16=1 , then the maximum value of p is

Find the coordinates of the foot of the perpendicular drawn from the origin to the plane 2x-3y+4z-6 = 0

ARIHANT MATHS-ELLIPSE-Exercise (Questions Asked In Previous 13 Years Exam)
  1. The 5th, 8th, and 11th terms of a GP are p, q and s respectively. Find...

    Text Solution

    |

  2. Is 309 a term of the AP 11, 17, 23….?

    Text Solution

    |

  3. A triangle A B C with fixed base B C , the vertex A moves such that co...

    Text Solution

    |

  4. The conic having parametric representation x=sqrt3(1-t^(2)/(1+t^(2))),...

    Text Solution

    |

  5. The ellipse x^2+""4y^2=""4 is inscribed in a rectangle aligned with...

    Text Solution

    |

  6. Tangents are drawn from the point P(3,4) to the ellipse x^(2)/9+y^(2)/...

    Text Solution

    |

  7. Tangents are drawn from the point P(3,4) to the ellipse x^(2)/9+y^(2)/...

    Text Solution

    |

  8. Tangents are drawn from the point P(3,4) to the ellipse x^(2)/9+y^(2)/...

    Text Solution

    |

  9. Find the equation of an ellipse whose axes lie along the coordinate ...

    Text Solution

    |

  10. The ellipse E1:(x^2)/9+(y^2)/4=1 is inscribed in a rectangle R whose s...

    Text Solution

    |

  11. Statement 1: An equation of a common tangent to the parabola y^2=16s...

    Text Solution

    |

  12. An ellipse is drawn by taking a diameter of the circle (x-1)^2+y^2=1 ...

    Text Solution

    |

  13. the equation of the circle passing through the foci of the ellip...

    Text Solution

    |

  14. A vertical line passing through the point (h, 0) intersects the ellips...

    Text Solution

    |

  15. The locus of the foot of prependicular drawn from the center of the el...

    Text Solution

    |

  16. Tangents are drawn to the ellipse x^2/9+y^2/5 = 1 at the end of latus ...

    Text Solution

    |

  17. Let E1 and E2, be two ellipses whose centers are at the origin.The maj...

    Text Solution

    |

  18. Suppose that the foci of the ellipse (x^2)/9+(y^2)/5=1 are (f1,0)a n d...

    Text Solution

    |

  19. If the tangents to the ellipse at M and N meet at R and the normal to ...

    Text Solution

    |

  20. The eccentricity of an ellipse whose centre is at the origin is 1/2. I...

    Text Solution

    |