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If y(x-y)^2=x, then int1/(x-3y)dx is eq...

If `y(x-y)^2=x`, then `int1/(x-3y)dx` is equal to
(A) `1/3log{(x-y)^2+1}`
(B) `1/4log{(x-y)^2-1}`
(C) `1/2log{(x-y)^2-1}`
(D) `1/6 log{(x^2-y^2-1}`

A

1

B

3

C

5

D

7

Text Solution

Verified by Experts

The correct Answer is:
C
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