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Let f(theta)= sin theta - cos^(2) theta-...

Let `f(theta)= sin theta - cos^(2) theta-1`, where `theta in R` and `m le f(theta) le M` .
Let N denotes the number of solution of the equation `f(theta)=0` in `[0,4 pi]` then the value of `log_(sqrt(m^(2)))(N)+log_(sqrt(m^(2)))((1)/(N+1))` is equal to

A

`1/2`

B

1

C

`(-1)/(2)`

D

`-1`

Text Solution

Verified by Experts

The correct Answer is:
C
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