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If x/acostheta+y/bsintheta=1,x/asintheta...

If `x/acostheta+y/bsintheta=1,x/asintheta-y/bcostheta=1`,' then prove that `x/a^2`+`y/b^2`=2'

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The correct Answer is:
`(x^(2))/(a^(2))+(y^(2))/(b^(2))=2`
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