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If alpha+beta=pi/2a n dbeta+gamma=alpha,...

If `alpha+beta=pi/2a n dbeta+gamma=alpha,` then `tanalpha` equals

A

(a) `2(tanbeta+tangamma)`

B

(b) `tanbeta+tangamma`

C

(c) `tanbeta+2tangamma`

D

(d) `2tanbeta+tangamma`

Text Solution

Verified by Experts

The correct Answer is:
`tan beta + 2 tan gamma`
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