If P=(tan(3^(n+1)theta)-tan theta) and Q...

If `P=(tan(3^(n+1)theta)-tan theta) and Q=sum_(r=0)^(n) (sin(3^(r )theta))/(cos(3^(r+1)theta))`, then

`P=2Q`

`P=3Q`

`2P=Q`

`3P=Q`

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