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For a positive integer n , let fn(theta)...

For a positive integer `n ,` let `f_n(theta)=(tantheta//2)(1+sectheta)(1+sec2theta)(1+sec4theta).......... (1+sec2^ntheta)`. Then (a)`f_2(pi/(16))=1` (b) `f_3(pi/(32))=1` (c)`f_4(pi/(64))=1` (d) `f_5(pi/(128))=1`

A

`f_(2)(pi/16)=1`

B

`f_(3) (pi/32)=1`

C

`f_(4) (pi/64)=1`

D

`f_(5)(pi/128)=1`

Text Solution

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A
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