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The figure shows two regions in the firs...

The figure shows two regions in the first quadrant. For curve `y = sin x^2`, A(t) is the area under the curve `y = sin x^2` from 0 to t and `B(t)` is the area of the triangle with vertices `O(0, 0), P(t, sin t^2) and M(t, 0)`. Find `Lim (t->0) (A(t)) / (B(t))`

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