A satellite is launched to a circular orbit of radius R and speed v. An accident causes it to be given a velocity component perpendicular to its orbital velocity(and away from the Earth).The ratio of this perpendicular velocity component to the original orbital velocity is x. The satellite is lost i.e. it escape from the earth . As it travels far away , the perpendicular distance of its line of motion from the earth is given by
`y=R/(sqrt(x^2-1))`
If R is reported with a `1%` error , `x=3+-0.08`. find the fractional error only

Explanation

To find the fractional error in the given problem, we start with the equation provided:

\[ y = \frac{R}{\sqrt{x^2 - 1}} \]

### Step 1: Identify the variables and their errors
We know:
- \( R \) has a 1% error, which can be expressed as:
\[ \frac{\Delta R}{R} = 0.01 \]
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