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0.17+ul(?)=5.17....

`0.17+ul(?)=5.17`.

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If 49 xx 17=833 , then the value of 0.0833 div 4.9 is: Options are (a) 0.17 (b) 0.0017 (c) 1.7 (d) 0.017 .

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If vec(DA)=veca,vec(AB)=vecb and vec(CB)=kveca where kgt0 and X,Y are the midpoint of DB and AC respectively such that |veca|=17 and |vec(XY)|=4, then k is equal to (A) 9/17 (B) 8/17 (C) 25/17 (D) 4/17

3/17 + 6/17 + (-4)/17

Evaluate 8/17-x for x=5/-17

17^2 . 17^5 = 17^7

(-7/17)^0=