If `f:R to R, g: R to R` are defined by `f(x)=3x-4` and `g(x)=2+3x`, then find `(g^(-1)of^(-1))(5)`.

If f:R rarr R,g:R rarr R are defined by f(x)=3x-4 and g(x)=2+3x ,then (g^(-1) of^(-1))(5)=

If f:R rarr R and g:R rarr R are define by f(x)=3x-4 and g(x)=2+3x , then (g^(-1)of^(-1))(5)=

If f:R rarr R and g:R rarr R are defined by f(x)=x-[x] and g(x)=[x] is x in R then f{g(x)}

Let R be the set of real number and the mapping f :R to R and g : R to R be defined by f (x)=5-x^(2)and g (x)=3x-4, then the value of (fog) (-1) is

If f: R to R and g: R to R are defined by f(x)=2x+3 and g(x)=x^(2)+7 , then the values of x such that g(f(x))=8 are

If f:R to R and g:R to R are defined by f(x)=(2x+3) and g(x)=x^(2)+7 , then the values of x such that g(f(x))=8 are

Let f : R to R and g : R to R be given by f (x) = x^(2) and g(x) =x ^(3) +1, then (fog) (x)