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A man can row upstream at 8 km/hr and do...

A man can row upstream at 8 km/hr and downstream at 10.6 km/hr. Find man's speed in still water and the rate of the current.

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To solve the problem of finding the man's speed in still water and the rate of the current, we can follow these steps: ### Step 1: Define Variables Let: - \( x \) = man's speed in still water (in km/hr) - \( y \) = rate of the current (in km/hr) ### Step 2: Set Up Equations From the problem, we know: 1. When rowing upstream, the effective speed is reduced by the current: \[ x - y = 8 \quad \text{(1)} \] 2. When rowing downstream, the effective speed is increased by the current: \[ x + y = 10.6 \quad \text{(2)} \] ### Step 3: Add the Two Equations Now, we can add equations (1) and (2): \[ (x - y) + (x + y) = 8 + 10.6 \] This simplifies to: \[ 2x = 18.6 \] ### Step 4: Solve for \( x \) Now, divide both sides by 2 to find \( x \): \[ x = \frac{18.6}{2} = 9.3 \text{ km/hr} \] So, the man's speed in still water is \( 9.3 \) km/hr. ### Step 5: Substitute \( x \) Back to Find \( y \) Now, we can substitute \( x \) back into either equation (1) or (2) to find \( y \). Let's use equation (2): \[ 9.3 + y = 10.6 \] Subtract \( 9.3 \) from both sides: \[ y = 10.6 - 9.3 = 1.3 \text{ km/hr} \] So, the rate of the current is \( 1.3 \) km/hr. ### Final Answer - Man's speed in still water: \( 9.3 \) km/hr - Rate of the current: \( 1.3 \) km/hr ---
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