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A source simultaneously emitting light at two wavelengths 400 nm and 800 nm is used in the Young's double slit experiment. If the intensity of light at the slit for each wavelength is `I_0`, then the maximum intensity that can be observed at any point on the screen is

A

`I_0`

B

`2I_0`

C

`4I_0`

D

`8I_0`

Text Solution

Verified by Experts

The correct Answer is:
D

At central maxima
Due to 400 nm = `4I_0`
Due to 800 nm = `4T_0`
Total Intensity = 8 `I_0`
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