The number of ions produced in water by dissolution of the complex having the empirical formular, `COCl_3 4NH_3` is

Options

A. 1
B. 2
C. 4
D. 3

Explanation

To determine the number of ions produced in water by the dissolution of the complex with the empirical formula \( \text{CoCl}_3 \cdot 4\text{NH}_3 \), we can follow these steps:

### Step 1: Identify the complex and its components
The given empirical formula is \( \text{CoCl}_3 \cdot 4\text{NH}_3 \). This indicates that cobalt (Co) is the central metal atom, with three chloride ions (Cl\(^-\)) and four ammonia molecules (NH\(_3\)) as ligands.

### Step 2: Determine the coordination number
The coordination number of cobalt in this complex is 6. This is because cobalt is surrounded by 4 ammonia molecules and 2 chloride ions (since there are 3 chloride ions, but only 2 are involved in the coordination sphere, the third chloride ion is outside the coordination sphere).

### Step 3: Write the dissociation equation
When this complex dissolves in water, it dissociates into its constituent ions. The dissociation can be represented as follows:

\[ [\text{Co(NH}_3\text{)}_4\text{Cl}_2]^+ + \text{Cl}^- \rightarrow \text{Co(NH}_3\text{)}_4^{2+} + 3\text{Cl}^- \]

### Step 4: Count the total number of ions produced
From the dissociation equation, we can see that:
- 1 cation: \( \text{Co(NH}_3\text{)}_4^{2+} \)
- 3 anions: \( 3 \text{Cl}^- \)

Thus, the total number of ions produced is:
\[ 1 + 3 = 4 \text{ ions} \]

### Final Answer
The number of ions produced in water by the dissolution of the complex \( \text{CoCl}_3 \cdot 4\text{NH}_3 \) is **4**.

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