A plant with genotype AABBCC is crossed with another plant with aabbcc genotype. How many different genotypes of pollens is possible in an F1 plant if these three loci follow independent assortment ?

Options

A. 8
B. 4
C. 2
D. 1

Answer

To solve the problem of determining how many different genotypes of pollen are possible in the F1 plant resulting from the cross of two plants with genotypes AABBCC and aabbcc, we can follow these steps:

### Step 1: Identify the Genotypes of the Parent Plants
- The first parent plant has the genotype AABBCC.
- The second parent plant has the genotype aabbcc.

### Step 2: Determine the Gametes Produced by Each Parent
- The first parent (AABBCC) can only produce one type of gamete because it is homozygous for all three loci: ABC.
- The second parent (aabbcc) can also only produce one type of gamete: abc.

### Step 3: Cross the Gametes to Form the F1 Generation
- When we cross the gametes from both parents, the F1 generation will have the genotype AaBbCc, which is heterozygous at all three loci.

### Step 4: Determine the Number of Different Genotypes of Pollen
- To find the number of different genotypes of pollen, we can use the formula for independent assortment: \( 2^n \), where \( n \) is the number of heterozygous loci.
- In this case, we have three heterozygous loci (A, B, and C), so \( n = 3 \).

### Step 5: Calculate the Number of Different Genotypes
- Using the formula:
\[ 2^n = 2^3 = 8 \]
- Therefore, there are 8 different genotypes of pollen possible in the F1 plant.

### Final Answer
The number of different genotypes of pollen possible in the F1 plant is **8**.

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