If `tantheta+sintheta=m,tantheta-sintheta=n`then show that `m^2-n^2=4sqrt(mn)`

If tantheta=t then tan2theta+sec2theta=

If tantheta+tan2theta+tanthetatan2theta=1 then theta equals to

(tantheta + sintheta)/(tantheta - sintheta) =(sectheta + 1 )/ (sectheta -1)

If a tantheta=b , then a cos 2theta+b sin 2theta=

sintheta/(1-cottheta)+costheta/(1-tantheta)=

If costheta-sintheta=sqrt2sintheta then costheta+sintheta is equal to

If "cosec " theta - sin theta = m, sec theta - cos theta =n , " then "(m^(2)n)^(2//3) + (mn^(2))^(2//3) =.................. A) 1 B) 2 C) 1/2 D) 0

If (1+tantheta)(1+tanphi)=2 then theta+phi=

int((sintheta+costheta))/sqrt(sin2theta)"d"theta=

If sintheta +cos theta =m and sec theta + cosec theta =n then n(m+1)(m-1) equals................ A) m B) n C) 2m D) 2n