If `sintheta=3/5`and `theta` ìs in the second quadrant, find : `sin(theta/2)`

If sintheta=3/5 and theta is in the second quadrant,find : cos(theta/2)

If sintheta=3/5 and theta ìs in the secondquadrant,find: tan(theta/2)

If sintheta=(-4)/5 and theta lies in the third quadrant, then cos(theta/2) =

If sin theta =(21)/(29) and theta lies in the second quadrant, find the value of sec theta + tan theta is

If sin theta =(24)/(25) and theta lies in the second quadrant, then sec theta + tan theta= ............ (A) -3 (B) -5 (C) -7 (D) -9

If tan theta =12/5 and theta lies in 1st quadrant, then find 5 sin theta-12 cos theta=?

If sin theta =-4/5 and theta lies in third quadrant, then the value of cos (theta/2) is ............... A) (1)/(sqrt5) B) -(1)/(sqrt5) C) sqrt((2)/(5)) D) -sqrt((2)/(5))

If sin theta=15/17 and theta lies in 1st quadrant, then cos theta=?

If sintheta=(2t)/(1+t^2) and theta lies in 2nd quadrant ,then costheta is equal to

If tan theta=(1)/sqrt(5) and theta lies in the first quadrant, the value of cos theta is :