In `triangleABC,A+B+C=pi`, show that `tan(A/2)tan(B/2)+tan(B/2)tan(C/2)+tan(C/2)tan(A/2)=1`

In triangleABC,A+B+C=pi ,show that tan2A+tan2B+tan2C=tan2Atan2Btan2C

If A+B+C=180^@ then sumtan(A/2)tan(B/2)=

In DeltaABC,1-tan.(A)/(2)tan.(B)/(2)=

In DeltaABC,tan.(A)/(2)+tan.(B)/(2) =

tan^(-1)1+tan^(-1)2+tan^(-1)3=

In any DeltaABC,("tan"(A)/(2)-"tan"(B)/(2))/("tan"(A)/(2)+"tan"(B)/(2)) is equal to

Let A, B and C are the angles of a plain triangle and tan(A/2)=1/3,tan(B/2)=2/3 then tan(C/2) is equal to............ A) 7/9 B) 2/9 C) 1/3 D) 2/3

If A+B+C=180^(@) , then Sigmatan.(A)/(2)tan.(B)/(2) is

tan 3A-tan 2A-tan A=

If A,B and C are the angles of a plain triangle and tan(A/2)=1/3 , tan(B/2)=2/3 , then tan(C/2) is equal to