Find the distance of `P(-1,1)`from the line `12(x+6)=5(y-2)`

Find the distance of the point A(-2,3) from the line 12x-5y-13=0

Find the distance of a point (2,4,-1) from the line (x+5)/1=(y+3)/4=(z-6)/(-9)

Find the distance of the point (-4,3) from the line 4(x+5)=3(y-6)

Find the distance of the origin from the line 12x+5y+78=0

Find the distance of the point (3,-5) from the line 3x-4y-26" =0 .

If the distance of the point P(1,-2,1) from the plane x+2y-2z=alpha , where alpha>0 , is 5, then the foot of the perpendicular from P to the place is