For the parabola `3y^2=16x` , find the parameter of the point. `(3,-4)`

For the parabola 3y^2=16x , find the parameter of the point. (27,-12)

For the parabola y^2=4x , find the coordinates of the point whose focal distance is 17.

The focal distance of a point on the parabola y^2=16x is 7, then the abscissa of the point is :

If the line x=9 cuts the parabola y^2=16x at A and B, find the length of AB.

Axis of the parabola y^2-16x+6y+89=0 , is:

The cartesian co - ordinates of the point on the parabola y^(2)=- 16x , whose parameter is (1)/(2), are

The point (2,2) lies on the parabola (x-3)^2=4a(y-1) find the focus and the equation of the directrix.

The area of the region bounded by the parabola (y-2)^(2) = x- 1 , the tangent to the parabola at the point (2,3) and the x-axis is

The distance between the vertex of the parabola y = x^2 - 4x + 3 and the centre of the circle x^2 = 9 - (y- 3)^2 is.