The parabola `x^2=4ay` passes through `(-2,1)` Find the co-ordinates ends of the LR and equation of thr directrix.

The point (2,2) lies on the parabola (x-3)^2=4a(y-1) find the focus and the equation of the directrix.

Find the centre, lenghts of the major axis and minor axis, LR, eccentricity, co-ordinates of the foci and equation of the directrices of the following : ((x+2)^2)/9+((y-1)^2)/4=1

Find the centre, lengths of the major axis and minor axis, LR, eccentricity, co-ordinates of the foci and equation of the directrices of the following : ((x-1)^2)/169+((y-2)^2)/144=1

Find the centre, lenghts of the major axis and minor axis, LR, eccentricity, co-ordinates of the foci and equation of the directrices of the following : 9x^2+5y^2-36x+10y-4=0

Find the centre, lenghts of the major axis and minor axis, LR, eccentricity, co-ordinates of the foci and equation of the directrices of the following : 2x^2+y^2+8x-6y-47=0

Find the length and ends of the LR of x^2+8y-16x+24=0

Find the length and ends of the LR of y^2-2x-8y-23=0

Find the equation of the parabola, given : focus (2,0) directrix x=-2

Find the equation of the parabola, given : vertex (0,0) directrix x=-2

Find the equation of the parabola, given : focus (-3,0) directrix x=3