Show that the equation of the parabola with `LR=4/3`, vertex (2,1) and focus `(-1/3,1)` is `3y^2-6y+4x-5=0`

The equation of the parabola with its vertex at (1, 1) and focus at (3, 1) is

The equation of the parabola whose vertex is at(2, -1) and focus at(2, -3), is

Find the equation of the parabola, given : vertex (-2,-3) focus (3,-3)

Find the equation of the parabola, given : vertex (0,0) focus (0,-3)

Find the equation of the parabola, given : vertex (0,0) focus (3,0)

Show that the equation of the parabola with vertex (2,5) and the equation of the directrix x=1 is (y-5)^2=-4(x-2)

The equation of the parabola with focus (1,-1) and directrix x + y + 3 =0 is

The equation of parabola whose vertex and focus are (0,4) and (0,2) respectively, is

Find the equation of the parabola whose focus is (5,3) and directrix is the line 3x-4y+1=0.

The vertex of the parabola y ^(2) -4y-x+3=0 is