An equilateral triangle is inscribed in the parabola `y^2=4ax` whose vertex is at the vertex of the parabola. Find the length of its side.

Draw equilateral triangle with side=4 cm.

The vertex of the parabola y ^(2) -4y-x+3=0 is

vertex of the parabola 9x^2-6x + 36y + 9 = 0 is

The vertex of the parabola x^2-2x-4y-7=0 , is:

Vertex of the parabola x ^(2) +4x + 2y -7=0 is

The vertex of the parabola x^2-4x-8y-20=0 , is

The vertex of the parabola y^2-3x+8y+31=0 , is

Vertex of the parabola y ^(2) + 2y + x=0 lies in the

Answer the following questions:The base of an equilateral triangle is the line x+y-2=0 and the vertex opposite to the base is (2,-1).Find the equations of the remaining sides.