If e and e' are the eccentricities of a hyperbola and its conjugate hyperbola respectively then prove that `1/e^2+1/(e')^2=1`

If e and e' are the eccentricities of a hyperbola and its conjugate, then the locus of the points (e,e') is

If e_1 and e_2 are the eccentricities of a hyperbola and its conjugate, prove that: 1/e_1^2+1/e_2^2=1

If e_1 and e_2 are the eccentricities of a parabola and ellipse respectively, then:

If e_1 and e_2 be the eccentricities of two conjugate hyperbola, then 1/e_1^2+1/e_2^2 is :

Find the eccentricity of the hyperbola wich is conjugate to the hyperbola x^2-3y^2=3 .

The eccentricity of the conjugate hyperbola of the hyperbola x^2-3y^2=1 is

If e_1 and e_2 are the eccentricities of the hyperbola x^2/a^2-y^2/b^2=1 and y^2/b^2-x^2/a^2=1 then show that 1/e_1^2+1/e_2^2=1 .

The eccentricity of the hyperbola x ^(2) - y^(2) =25 is

If e and e' are the eccentricities of the ellipse 5x^(2) + 9 y^(2) = 45 and the hyperbola 5x^(2) - 4y^(2) = 45 respectively , then ee' is equal to

The eccentricity of the hyperbola y^2/25-x^2/144=1 , is: