the foci of the ellipse `x^2/16-y^2/b^2=1` and the hyperbola `x^2/144-y^2/81=1/25` coincide. Then the value of `b^2` is :

The foci of the ellipse x^2/16+y^2/b^2=1 and hyperbola x^2/144-y^2/81=1/25 coincide. Then the value of b^2 is :

If the foci of the ellipse (x^(2))/(16)+(y^(2))/(b^(2))=1 and the hyperbola (x^(2))/(144)-(y^(2))/(81)=(1)/(25) coincide, the find the value of b^(2) .

The foci of the ellipse 25x^2+36y^2=225 are

Find the area of ellipse x^2/6+y^2/25=1 .

The foci of the hyperbola 9x^2-16 y^2=144 are

The latus rectum of the ellipse 9x^2+16y^2=144 , is:

IF the equation of the ellipse is x^2/a^2+y^2/b^2=1 then SP+S'P=

The focai of the conjugate hyperbola of the hypberbola x^(2)/144 - y^(2)/25=1 are