Tangents are drawn through a point P to the ellipse `4x^2+5y^2=20` having inclinations `theta_1` and `theta_2` such that `tantheta_1+tantheta_2=2`. Find the equation of the locus of P.

If tantheta+tan2theta+tanthetatan2theta=1 then theta equals to

Answer the following:Tangents to the circle x^2+y^2=a^2 with inclinations, theta_1 and theta_2 intersect in P.Find the locus of point P such that tantheta_1+tantheta_2=0

If tan theta+tan 2theta+tan 3theta = tantheta tan 2theta tan 3theta then the general value of theta is

P and Q are two points on the ellipse x^2/a^2+y^2/b^2=1 with eccentric angles theta_1 and theta_2 . Find the equation of the locus of the point of intersection of the tangents at P and Q if theta_1+theta_2=pi/2 .

Answer the following:Tangents to the circle x^2+y^2=a^2 with inclinations, theta_1 and theta_2 intersect in P.Find the locus of point P such that cottheta_1+cottheta_2=5

Answer the following:Tangents to the circle x^2+y^2=a^2 with inclinations, theta_1 and theta_2 intersect in P.Find the locus of point P such that cottheta_1.cottheta_2=c

If tantheta=t then tan2theta+sec2theta=

If a tantheta=b , then a cos 2theta+b sin 2theta=

If tantheta_1=kcottheta_2 then (cos(theta_1+theta_2))/(cos(theta_1-theta_2))=