Home
Class 11
MATHS
An ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 pas...

An ellipse `(x^2)/(a^2)+(y^2)/(b^2)=1` passes through the point `(-3,1)` and its eccentricity is `sqrt(2/5)` . The equation of the ellipse is

A

`4sqrt(2/5)`

B

`8sqrt(2/3)`

C

`4sqrt(2/3)`

D

`8sqrt(2/5)`

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

The hyperbola x^2/a^2-y^2/b^2=1 passes through the point (2,3) and has eccentricity 2, then the transverse axis of the hyperbola has the length:

If the area of the auxiliary circle of the ellipse (x ^(2))/(a ^(2)) + (y ^(2))/(b ^(2)) =1 (a gt b) is twice the area of the ellipse, then the eccentricity of the ellipse is

For the ellipse (x ^(2))/(64) + (y^(2))/(28)=1, the eccentricity is

Find the equation of an ellipse hose axes lie along the coordinate axes, which passes through the point (-3,1) and has eccentricity equal to sqrt(2//5)dot

Let the equation of an ellipse be (x^(2))/(144) + (y^(2))/(25) = 1 . Then the radius of the circle with centre (0 , sqrt(2)) and passing through the foci of the ellipse is _

Equation of the ellipse whose axes are the axes of coordinates and which passes through the point (-3,""1) and has eccentricity sqrt(2/5) is: (1) 3x^2+""5y^2-32""=""0 (2) 5x^2+""3y^2-48""=""0 (3) 3x^2+""5y^2-15""=""0 (4) 5x^2+""3y^2-32""=""0

The ellipse x^2+""4y^2=""4 is inscribed in a rectangle aligned with the coordinate axes, which in turn is inscribed in another ellipse that passes through the point (4, 0). Then the equation of the ellipse is

The distance between the foci of an ellipse is 16 and eccentricity is 1/2. Length of the major axis of the ellipse is

Find the equation of the ellipse in the form ((x-h)^2)/a^2+((y-k)^2)/b^2=1(a>b) , given : vertices (2,-2) and (2,-4) and eccentricity is 1/3 and distance between the foci is 4.