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The foci of the ellipse x^2/16+y^2/b^2=1...

The foci of the ellipse `x^2/16+y^2/b^2=1` and hyperbola `x^2/144-y^2/81=1/25` coincide. Then the value of `b^2` is :

A

5

B

7

C

9

D

8

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