Home
Class 11
MATHS
The equation of hyperbola having focus a...

The equation of hyperbola having focus at (3,0), the line `x=5` as directrix and eccentricity `3/2` is:

A

`5x^2-4y^2+66x+189=0`

B

`5x^2-4y^2-66x+189=0`

C

`5x^2-4y^2+66x-189=0`

D

`4x^2-5y^2+66x-189=0`

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of the parabola with focus at (-6,0) and the line x+2=0 as directrix is

The equation of the parabola with (-3, 0) and focus and x+5=0 as directrix, is

The equation of the parabola with the focus (3,0) and directrix x+3=0 is

The equation of the hyperbola in standard form, if the foci are (+-10,0) and eccentricity 5/2 is

The equation of hyperbola whose focus is (5,0) and corresponding directrix is x=4 , is:

The equation of an ellipse whose focus is (-1,1), directrix is x -y + 3=0 and eccentricity is 1/2, is given by

Find the equation of the parabola, given : focus (-3,0) directrix x=3

The equation of the conic with focus at (1,-1), directrix along x -y + 1=0 and with eccentricity sqrt2, is

The equation of the parabola with focus (1,-1) and directrix x + y + 3 =0 is

The equation of the hyperbola whose foci are (-2, 0) and (2,0) and eccentricity is 2 is given by: a) x^3-3y^2=3 b) 3x^2-y^2=3 c) -x^2+3y^2=3 d) -3x^2+y^2=3