Find the co-ordinates of vertex, focus and equation of the directrux and the axis of the parabola `y=x^2-2x+3`.

Find co-ordinates of focus, vertex and the equation of directrix and the axis of the parabola y=x^2-2x+3

The vertex of the parabola x^2-2x-4y-7=0 , is:

Find the centre, lenghts of the major axis and minor axis, LR, eccentricity, co-ordinates of the foci and equation of the directrices of the following : 2x^2+y^2+8x-6y-47=0

Find the centre, lenghts of the major axis and minor axis, LR, eccentricity, co-ordinates of the foci and equation of the directrices of the following : 9x^2+5y^2-36x+10y-4=0

The vertex of the parabola y^2-3x+8y+31=0 , is

Find the centre, lengths of the major axis and minor axis, LR, eccentricity, co-ordinates of the foci and equation of the directrices of the following : ((x-1)^2)/169+((y-2)^2)/144=1

Find the centre, lenghts of the major axis and minor axis, LR, eccentricity, co-ordinates of the foci and equation of the directrices of the following : ((x+2)^2)/9+((y-1)^2)/4=1

The distance between the vertex and the focus of the parabola x ^(2) -2x + 3y-2 =0 is