Find 0.9 + 0.99 + 0.999 + … + to n terms

If (1 + 3 + 5 + 7 …. Up to n terms) / (2 + 4 + 6 + 8 +… up to n terms)= 0.95, find n.

If (1xx3 + 2xx5 + 3xx7 + ….. upto n terms) / ( 1^3 + 2^3 + 3^3 + …… upto n terms) = 5/9, find the value of n.

Find sqrt 0.9 by using first four terms of the binomial expansion.

If ( 1^2 + 2^2 + 3^2 + ……………… to 'n' terms) / ( 1.3 + 2.5 + 3.7 +……………. To 'n' terms) = 9/5 find 'n'.

The sum to n terms of the series 9 + 99 + 999 + ……. Is

Find the sum to n terms 0.3+0.33+0.333+ ... n terms