If the function `f(x) = (1-sinx)/(pi-2x)^2`, `x!=pi/2` is continuous at `x=pi/4`, then find `f(pi/2)`.

If f(x) = {((1-sinx)/(pi-2x), ",", x != pi/2),(lambda, ",", x = pi/2):} , be continuous at x = (pi)/2 , then the value of lambda is

The function f(x) = (1-sin x + cos x)/(1+sin x + cosx) is not defined at x = pi . The value of f(pi) , so that f(x) is continuous at x = pi is

If f(x) = (tan(pi/4-x))/(cot2x), x != pi/4 , is continuous in (0, pi/2) , then f((pi)/(4)) is equal to